Problem
NT-B1-M09-P007 Divisors of \(1000\)
#7
★★☆☆☆ Level 2 of 5
Find the number of positive divisors of \(1000\).
\(1000=10^3\).
\(1000=2^3\cdot5^3\). Therefore \(\tau(1000)=(3+1)(3+1)=16\).
Good example with equal exponents.