Problem
NT-B1-M09-P006 Divisors of \(360\)
#6
★★☆☆☆ Level 2 of 5
Find \(\tau(360)\).
Use \(360=2^3\cdot3^2\cdot5\).
\(\tau(360)=(3+1)(2+1)(1+1)=4\cdot3\cdot2=24\).
Repeats the example as independent practice.