Problem
NT-B2-M06-P010 The Form \(5^{2n}-1\)
#10
★★★☆☆ Level 3 of 5
Find \(v_3(5^{2n}-1)\).
\(3\mid5+1\), and the exponent \(2n\) is even.
By the \(a+b\) case, \(v_3(5^{2n}-1)=v_3(6)+v_3(2n)=1+v_3(n)\).
Shows how the even exponent enters the formula.