Problem
NT-B1-M10-P002 Divisibility by \(11\)
#2
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Check whether \(9182734\) is divisible by \(11\).
Compute the alternating sum of digits.
From the right, \(4-3+7-2+8-1+9=22\). Since \(22\) is divisible by \(11\), \(9182734\) is divisible by \(11\).
It is useful to require the explanation via \(10\equiv-1\pmod{11}\).